The Golden Ratio = 1.61803399

As we approach Pi Day (after all it is Sunday, 3-14), I though I’d give a shout out to another magical proportion, the Golden Ratio 1.61803399. Too bad there is no January the 61st. Apparently, Marc Umile (a guy with way too much free time) holds 10th place (What! only 10th place!? who is #1?) in the world for pi memorization — he typed out 15,314 digits from memory in 2007. While Marc continues to memorize Pi, I prefer to appreciate the fine proportions of Phi as exhibited in the Fibonacci spiral below.

1 Response to “The Golden Ratio = 1.61803399”

  1. 1 iandanaross June 14, 2010 at 9:42 pm


    It seems mathematically possible that PI is stealing PHI’s rightful
    place as a constant. The square root of 1/PHI = 0.7861513778. PI/4 = 0.78539816339744830961566084581988 : 1/8 the circumference of the unit circle? 0.7861513778 * 8 = 6.2892110224 ; 0.78539816339744830961566084581988 * 8 = 6.283185307179586476925286766552; 6.2892110224 – 6.283185307179586476925286766552 = 0.006025715220413523074713233448. Intuitively, the estimate 3.1415926535897932384626433832795 could possibly be out 0.0030128576102067615373566167204971, a significantly small number.

    I have figures using differentiation: an exact math, which strongly suggest the circumference of the unit circle is exactly 6.2892110224 and the area of the said circle is exactly 3.1446055112: The {square root of 1/PHI (1/1.61803399)}, multiplied by four.

    Fibonacci shows up everywhere in nature and all over the unit circle and I can prove that circles are formed by golden section or the golden mean and that circles carry the logarithmic signature of the Fibonacci numbers.

    Nascar and the military use 3.144; they don’t know why it works, but that it does. Perhaps the 61st day of every year should be held in commemoration for Fibonacci. There are those who exploit man with a small margin of 0.0030128576102067615373566167204971, hoping none will ever see it, just like cooking the books? These will gr eave the 61st of every year.

    If your interested, contact me at

    Ian Ross

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